(b) If we fix T at the start and S at the end of the word, we have to permute 7 distinct letters in 7 places. Thus, the number of different permutations (or arrangements) of the letters of this word is 9P 9 = 9!. (a) There are 9 distinct letters in the given word. Here are some applications of permutations in real life scenarios.Įxample 1: (a) How many words can be formed using the letters of the word TRIANGLES? (b) How many of these words start with T and end with S? The number of permutations of 'n' things out of which 'r' things are taken and where the repetition is allowed is given by the formula: n r., 'r n' objects belong to the n th type is n! / (r 1! × r 2! ×.
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